Added the Admin Panel #4
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WalkthroughIntroduces a new admin workflow with persistent user management. Admin login now loops for credential validation with attempt counters. New functions load and save user data to persistent storage. Admin panel provides UI for managing users (change username, list users, delete user) triggered after successful authentication. Changes
Sequence DiagramsequenceDiagram
actor Admin
participant AuthSystem as Authentication
participant AdminPanel as Admin Panel
participant FileSystem as File Storage
rect rgb(220, 240, 255)
Note over Admin,FileSystem: Admin Login Flow
Admin->>AuthSystem: Enter credentials
AuthSystem->>AuthSystem: Validate credentials
alt Credentials invalid
AuthSystem->>Admin: Prompt retry
Admin->>AuthSystem: Re-enter credentials
else Credentials valid
AuthSystem->>FileSystem: load_users()
FileSystem-->>AuthSystem: User data
AuthSystem->>AdminPanel: Trigger adminpanel
end
end
rect rgb(240, 220, 255)
Note over Admin,FileSystem: Admin Operations
Admin->>AdminPanel: Select operation
alt Change Username / Delete User
AdminPanel->>FileSystem: load_users()
FileSystem-->>AdminPanel: User data
AdminPanel->>AdminPanel: Modify user(s)
AdminPanel->>FileSystem: save_users(updated)
else See All Users
AdminPanel->>FileSystem: load_users()
FileSystem-->>AdminPanel: User data
AdminPanel->>Admin: Display users
end
end
Estimated Code Review Effort🎯 3 (Moderate) | ⏱️ ~20 minutes
Poem
Pre-merge checks and finishing touches❌ Failed checks (1 warning)
✅ Passed checks (2 passed)
✨ Finishing touches
🧪 Generate unit tests (beta)
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Actionable comments posted: 5
🧹 Nitpick comments (1)
Backend user system/lgoin system.py (1)
157-170: Good extraction; consider refactoring existing functions to use it.This helper consolidates the user loading logic. The same pattern is duplicated in
signup()(lines 51-61) andlogin()(lines 104-111). Consider refactoring those functions to useload_users()for consistency.
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Configuration used: defaults
Review profile: CHILL
Plan: Pro
📒 Files selected for processing (1)
Backend user system/lgoin system.py(2 hunks)
🧰 Additional context used
🪛 Ruff (0.14.8)
Backend user system/lgoin system.py
181-181: Local variable users is assigned to but never used
Remove assignment to unused variable users
(F841)
🔇 Additional comments (2)
Backend user system/lgoin system.py (2)
173-177: LGTM!Good helper extraction. Consider using this in
signup()(lines 90-92) to eliminate duplication.
236-274: LGTM!Both
see_all_usersanddelete_userare well-implemented with proper validation and user confirmation for destructive operations.
Comment on lines
+140
to
+152
| while login_username != ADMIN_USER: | ||
| print("Invalid Username") | ||
| login_username = input("What is your Username: ") | ||
|
|
||
| return False | ||
| if login_password != Admin_password: | ||
| while login_password != Admin_password: | ||
| print("Invalid Password") | ||
| return False | ||
| passwordattempts = passwordattempts+1 | ||
| print("Remaining Attempts:",passwordattempts) | ||
| if passwordattempts >= 3: | ||
| print("You are not an Admin Nice try") | ||
| main() | ||
| login_password = input("What is your Password: ") |
There was a problem hiding this comment.
Critical logic bug: return False executes inside the while loop.
The return False on line 144 is indented inside the while loop, causing the function to immediately return after the first invalid username attempt instead of allowing retry. Similarly, the password validation loop structure is problematic.
Additionally:
- Line 148 shows "Remaining Attempts" but displays the count going up (0→1→2), which is confusing.
- Line 151 uses recursive
main()call which can cause stack overflow with repeated failures.
Apply this diff to fix the logic:
def adminlogin():
global passwordattempts
login_username = input("What is your Username: ")
- login_password = input("What is your Password: ")
while login_username != ADMIN_USER:
print("Invalid Username")
login_username = input("What is your Username: ")
- return False
+ login_password = input("What is your Password: ")
+
while login_password != Admin_password:
print("Invalid Password")
- passwordattempts = passwordattempts+1
- print("Remaining Attempts:",passwordattempts)
+ passwordattempts += 1
+ print(f"Failed Attempts: {passwordattempts}/3")
if passwordattempts >= 3:
print("You are not an Admin Nice try")
- main()
+ return False
login_password = input("What is your Password: ")
print("Welcome Admin")
return TrueCommittable suggestion skipped: line range outside the PR's diff.
🤖 Prompt for AI Agents
In Backend user system/lgoin system.py around lines 140 to 152, the username
loop currently returns False inside the while loop which causes an immediate
exit after the first invalid entry and the password loop increments attempts and
calls main() recursively; fix by removing the in-loop return so the username
while loop keeps prompting until a match (or exits after a controlled max
attempts), rework the password loop to decrement a remaining_attempts counter
(or calculate remaining as max_attempts - attempts) so the printed "Remaining
Attempts" counts down, and replace the recursive main() call with an iterative
control flow (e.g., break/continue to outer loop or return to caller) to avoid
recursion and possible stack overflow; ensure variable names (ADMIN_USER vs
Admin_password) are used consistently and move any final return False to after
loops when authentication fails.
Comment on lines
+173
to
+177
| def save_users(users): | ||
| """Save users to userdata.txt file""" | ||
| with open('userdata.txt', 'w') as f: | ||
| for username, password in users.items(): | ||
| f.write(f"{username}:{password}\n") |
There was a problem hiding this comment.
Security: Passwords are stored in plaintext.
Both user credentials and this save function store passwords in plaintext. For any production use, passwords should be hashed using a secure algorithm like bcrypt or argon2.
Example using hashlib (for learning; prefer bcrypt for production):
import hashlib
def hash_password(password):
return hashlib.sha256(password.encode()).hexdigest()
def save_users(users):
"""Save users to userdata.txt file (passwords should already be hashed)"""
with open('userdata.txt', 'w') as f:
for username, password_hash in users.items():
f.write(f"{username}:{password_hash}\n")Note: This would require updating signup() and login() to hash passwords during registration and verification.
🤖 Prompt for AI Agents
In Backend user system/lgoin system.py around lines 173 to 177, the save_users
function writes plaintext passwords to userdata.txt; change it to store password
hashes instead: update the signup flow to hash new passwords with a secure
algorithm (preferably bcrypt or argon2) and store the resulting hash in the
users dict, change login to verify incoming passwords against the stored hash
using the corresponding verify function, and modify save_users to write
username:password_hash lines (and load_users to expect hashes). Ensure you add
the chosen hashing library to dependencies and handle errors on read/write
consistently.
Comment on lines
+180
to
+205
| def adminpanel(): | ||
| users = load_users() # Load users at the start | ||
|
|
||
| Rabbit.sleep(1) | ||
| print("\n=== Admin Panel ===") | ||
| print("1: Change a Users Username") | ||
| print("2: See all users") | ||
| print("3: Delete a User account") | ||
| print("4: Exit Admin Panel") | ||
|
|
||
| choice = input("\nEnter your choice (1-4): ").strip() | ||
|
|
||
| if choice == "1": | ||
| change_username() | ||
| elif choice == "2": | ||
| see_all_users() | ||
| elif choice == "3": | ||
| delete_user() | ||
| elif choice == "4": | ||
| print("Exiting admin panel...") | ||
| main() | ||
| else: | ||
| print("Invalid choice. Please try again.") | ||
|
|
||
| # Loop back to admin panel | ||
| adminpanel() |
There was a problem hiding this comment.
Control flow issues and unused variable.
- Line 181:
usersis loaded but never used (as flagged by static analysis). - Lines 200 + 205: When user chooses "4",
main()is called, but after it returns,adminpanel()is called again unconditionally on line 205, causing unexpected re-entry. - Using recursion for the menu loop can cause stack overflow with extended use.
Apply this diff to fix:
def adminpanel():
- users = load_users() # Load users at the start
-
- Rabbit.sleep(1)
- print("\n=== Admin Panel ===")
- print("1: Change a Users Username")
- print("2: See all users")
- print("3: Delete a User account")
- print("4: Exit Admin Panel")
-
- choice = input("\nEnter your choice (1-4): ").strip()
-
- if choice == "1":
- change_username()
- elif choice == "2":
- see_all_users()
- elif choice == "3":
- delete_user()
- elif choice == "4":
- print("Exiting admin panel...")
- main()
- else:
- print("Invalid choice. Please try again.")
-
- # Loop back to admin panel
- adminpanel()
+ while True:
+ Rabbit.sleep(1)
+ print("\n=== Admin Panel ===")
+ print("1: Change a Users Username")
+ print("2: See all users")
+ print("3: Delete a User account")
+ print("4: Exit Admin Panel")
+
+ choice = input("\nEnter your choice (1-4): ").strip()
+
+ if choice == "1":
+ change_username()
+ elif choice == "2":
+ see_all_users()
+ elif choice == "3":
+ delete_user()
+ elif choice == "4":
+ print("Exiting admin panel...")
+ return # Return to caller instead of calling main()
+ else:
+ print("Invalid choice. Please try again.")📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
Suggested change
| def adminpanel(): | |
| users = load_users() # Load users at the start | |
| Rabbit.sleep(1) | |
| print("\n=== Admin Panel ===") | |
| print("1: Change a Users Username") | |
| print("2: See all users") | |
| print("3: Delete a User account") | |
| print("4: Exit Admin Panel") | |
| choice = input("\nEnter your choice (1-4): ").strip() | |
| if choice == "1": | |
| change_username() | |
| elif choice == "2": | |
| see_all_users() | |
| elif choice == "3": | |
| delete_user() | |
| elif choice == "4": | |
| print("Exiting admin panel...") | |
| main() | |
| else: | |
| print("Invalid choice. Please try again.") | |
| # Loop back to admin panel | |
| adminpanel() | |
| def adminpanel(): | |
| while True: | |
| Rabbit.sleep(1) | |
| print("\n=== Admin Panel ===") | |
| print("1: Change a Users Username") | |
| print("2: See all users") | |
| print("3: Delete a User account") | |
| print("4: Exit Admin Panel") | |
| choice = input("\nEnter your choice (1-4): ").strip() | |
| if choice == "1": | |
| change_username() | |
| elif choice == "2": | |
| see_all_users() | |
| elif choice == "3": | |
| delete_user() | |
| elif choice == "4": | |
| print("Exiting admin panel...") | |
| return # Return to caller instead of calling main() | |
| else: | |
| print("Invalid choice. Please try again.") |
🧰 Tools
🪛 Ruff (0.14.8)
181-181: Local variable users is assigned to but never used
Remove assignment to unused variable users
(F841)
🤖 Prompt for AI Agents
In Backend user system/lgoin system.py around lines 180 to 205, remove the
unused users = load_users() or use it where needed, replace the recursive
adminpanel() calls with an explicit while True loop for the menu, handle choices
inside the loop, and on choice "4" break/return so you do not call main() and
then re-enter the admin panel; ensure there is no unconditional recursive
adminpanel() at the end and avoid deep recursion to prevent stack overflow.
Comment on lines
+224
to
+228
| new_username = input("Enter the new username: ").strip() | ||
|
|
||
| if new_username in users: | ||
| print(f"Username '{new_username}' already exists.") | ||
| return |
There was a problem hiding this comment.
Missing username validation.
The new username isn't validated for length (max 12 characters) or empty strings, unlike signup() which enforces these constraints. This allows creating usernames that bypass signup rules.
new_username = input("Enter the new username: ").strip()
+ if not new_username:
+ print("Username cannot be empty.")
+ return
+
+ if len(new_username) > 12:
+ print("Username too long (max 12 characters).")
+ return
+
if new_username in users:
print(f"Username '{new_username}' already exists.")
return📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
Suggested change
| new_username = input("Enter the new username: ").strip() | |
| if new_username in users: | |
| print(f"Username '{new_username}' already exists.") | |
| return | |
| new_username = input("Enter the new username: ").strip() | |
| if not new_username: | |
| print("Username cannot be empty.") | |
| return | |
| if len(new_username) > 12: | |
| print("Username too long (max 12 characters).") | |
| return | |
| if new_username in users: | |
| print(f"Username '{new_username}' already exists.") | |
| return |
🤖 Prompt for AI Agents
In Backend user system/lgoin system.py around lines 224 to 228, the new_username
input lacks the same validation as signup; add checks after stripping to ensure
the username is not empty and does not exceed 12 characters (e.g., if not
new_username or len(new_username) > 12: print an explanatory message and
return), and keep the existing duplicate check; mirror the exact validation
rules used by signup to prevent bypassing signup constraints.
Comment on lines
291
to
+297
| if adminlogin(): | ||
| print("Admin access granted!") | ||
| global passwordattempts | ||
| passwordattempts = 0 | ||
| adminpanel() | ||
| else: | ||
| print("Admin login failed.") | ||
| main() |
There was a problem hiding this comment.
Duplicate global declaration and recursive calls.
- Line 293 is a redundant
global passwordattemptsdeclaration (already declared at line 277) and placing it inside a nested block causes aSyntaxWarning. - Line 297 uses recursion for retrying, which can cause stack overflow with repeated failures.
Consider using a loop-based approach for the main menu:
def main():
- global passwordattempts
- print("1. Signup")
- print("2. Login")
- choice = input("Choose: ")
-
- if choice == "1":
- signup()
- elif choice == "2":
- if login():
- print("Welcome! You are now logged in.")
- # Continue with your program
- else:
- print("Login failed. Please try again.")
- elif choice == login_secret:
- if adminlogin():
- print("Admin access granted!")
- global passwordattempts
- passwordattempts = 0
- adminpanel()
- else:
- main()
- else:
- print("Invalid choice")
+ global passwordattempts
+ while True:
+ print("1. Signup")
+ print("2. Login")
+ choice = input("Choose: ")
+
+ if choice == "1":
+ signup()
+ elif choice == "2":
+ if login():
+ print("Welcome! You are now logged in.")
+ # Continue with your program
+ break
+ else:
+ print("Login failed. Please try again.")
+ elif choice == login_secret:
+ if adminlogin():
+ print("Admin access granted!")
+ passwordattempts = 0
+ adminpanel()
+ # Loop continues if adminlogin fails
+ else:
+ print("Invalid choice")Committable suggestion skipped: line range outside the PR's diff.
🤖 Prompt for AI Agents
In Backend user system/lgoin system.py around lines 291 to 297, remove the
redundant in-block "global passwordattempts" (it's already declared at line 277)
and avoid the recursive call to main() for retries; instead ensure the global is
declared once at the top of the function or module and refactor control flow to
use a loop-based retry mechanism (e.g., while/for loop) that resets
passwordattempts on successful adminlogin() and calls adminpanel() directly
without recursion, and on failure continues the loop or exits gracefully to
prevent stack growth.
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